1. ans: 11 cal; use Q=mc*DT=10*0.215*5.

2. ans: 94,000 Joules; same as #1- mc*DT=300*1*75*4.186; the last factor converts calories to Joules.

3. ans: 115 deg; use DT=Q/mc, where Q= 1/2 initial KE in calories = 0.25*0.003*240*240/4.186.

4. ans: -1.8 øC; heat lost from water =mL =270 cal. Then use DT=Q/mc =1.8 (neg because heat lost).

5. ans: 1.6 kg; heat required to cool the tea is Q=mc*DT =126 kcal. Heat used to melt ice = m*80; set equal and solve for m.

6. ans: 29 øC; DT=Q/mc, =(800*10*60/4.186 cal)/(4000*1).