2. The earth turns through 2p rad in one day (86,400 s). Thus, w = 2p rad / 86400 s = 7.27x10^-5 rad/s.

3. q = s/r = 2.50x1.50 = 1.67 rad = 95.7°.

4. w_o = 3600 rev/min = 377 rad/s,
q = 50.0 rev = 314 rad,
and w_f = 0.
Use w_f² = w_o² + 2aq.
0 = (377 rad/s)² + 2a(314 rad)

5. w = 200 rev/min = 20.9 rad/s
a_cent = v²/r = w²r = (0.500 m)(20.9 rad/s)² = 218 m/s².

6. The deceleration a of the rim of each tire is 2.00 m/s², and so the angular acceleration of each wheel is given by
a = a/r = –2.00 / 0.300 m = –6.67 rad/s².
The initial angular speed w_o of each wheel is v/r = 30.0 / 0.300 = 100 rad/s.
Use w_f² = w_o² + 2aq again.
q = –w_o²/2a = (–100)²/2(–6.67) = 750 rad = 119 rev.